آزمایش عملی سنتز نانو ذره کادمیم سولفید
Hexadecyltrimethylammonium bromide has a long hydrophobic chain and a polar head group.

The molecule does not dissolve well in either aqueous or organic solvents. In an organic solvent containing a small amount of water the hexadecyltrimethylammonium bromide traps the aqueous portion in a micelle sphere with the polar heads facing in and the non-polar tails facing out. The relative amount of pentanol cosurfactant controls the size of the micelle.
A water-in-oil microemulsion droplet.
This static picturedoes not properly convey "the dynamic reality of the aggregates."
Figure based on J. Phys. Chem. 100, 3190-3198 (1996).
2 with similar micelles containing Na2S produces nanoparticle CdS since the aqueous solution serves as a nanoreactor and the particles cannot grow bigger than the micelle. The pentanol also acts as a capping agent to stabilize the CdS particles. The formation of CdS nanoparticles can be detected by spectroscopy since quantum size effects make the visible absorption spectra different than that of bulk CdS
To the second test tube, add 0.1 mL (3 drops) of 0.012 M Na2S. The solution will clear as hexadecyltrimethylammonium bromide micelles containing Na2S form.
Materials
- Stock Solutions for hundreds of batches
- 0.012 M CdCl2: Dissolve 0.110 g in 50 mL distilled water. This solution keeps for months.
- 0.012 M Na2S.9H2O: Dissolve 0.144 g in 50 mL distilled water. This solution does not keep well.
- hexadecyltrimethylammonium bromide (Aldrich 855820 Cetyltrimethylammonium bromide)
- heptane
- pentanol
- Test tubes, ring stand, test tube clamps
- plastic dropper
- 1/4" magnetic stir bar, magnetic stirrer
- Cuvet and absorption spectrometer
Equipment
Calculations
The x-intercept of the linear portion of the absorbance as a function of wavelength graph is a measure of Eg.
Eg = h c / λ
h = 6.626x10-34 J s
c = 2.998x108 m/s
e = 1.602x10-19 C
ε0 = 8.854x10-12 C2/N/m2
m0 = 9.110x10-31 kg
CdS
λbulk = 512 nm
ε = 5.7
me* = 0.19
mh* = 0.80
CdSe
λbulk = 709 nm
ε = 10.6
me* = 0.13
mh* = 0.45
ZnO
λbulk = 365 nm
ε = 8.66
me* = 0.24
mh* = 0.59
The effective mass model suggests 
where r is the radius of the nanoparticle. The second term is the
particle-in-a-box confinement energy for an electron-hole pair in a
spherical quantum dot
and the third term is the Coulomb attraction between an electron and
hole modified by the screening of charges by the crystal.
After multiplying by r2, rearranging, and using the quadratic formula, 
What is the diameter of the nanoparticles?







